C# 打开某个应用程序

 ProcessStartInfo psi = new ProcessStartInfo();

                        psi.FileName = @item;

                        psi.UseShellExecute = false;

                        FileInfo theFile = new FileInfo(@item);
                        string dir = theFile.DirectoryName;
                        psi.WorkingDirectory = dir;

                        psi.CreateNoWindow = true;

                        Process.Start(psi);

                        Thread.Sleep(2000);